Question

39y^3(50y^2-98) divide 26y^2(5y-7)

Answer 1

$39 {y}^{3} \times( 50 {y}^{2} - 98) \div 26 {y}^{2} (5y - 7)$
$3y(5 {y}^{2} - 98) \div 2(5y - 7)$
$(150 {y}^{3} - 294y) \div (10y - 14)$
$(75 {y}^{3} - 147) \div (5y - 7)$

Answer 2

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