Math, asked by rakhijindal3008, 1 month ago

39y3(50y2-98)
26y2(5y-7)

Answers

Answered by Limafahar

1

$39 {}^{3} (50y {}^{2} - 98) = 1950y {}^{5} - 3822y {}^{3}$

$26y {}^{2} (5y - 7) = 130y {}^{3} - 182y {}^{2}$

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