Question

(3a + 1)^2 + (b -1)^2 + (2c - 3)^2 = 0. then 3a + b + 2c = ?
say the answer step by step
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Answer 1

3a + b + 2c = 3 … Eq. (1)

a + 3b + 2c = 1 … Eq. (2)

Subtract Eq. (2) from Eq. (1) and you get

2a - 2b = 2, or a - b = 1

Thus b = a - 1

Put this value of b in Eq. (1) to get 3a + a - 1 + 2c = 3 or 4a + 2c = 4

So. 2a + c = 2.

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Answer 2

#prakash...........༆༆༆