(3a + 1) (3a - 2)(3a + 4) by algebraic identities
Answers
Step-by-step explanation:
27a' + 27a? - 18a 8 -
Step-by-step explanation:
(3a + 1) (3a - 2) (3a + 4)
Expand (3a + 1) (3a – 2)
(3a + 1) (3a – 2)
Apply FOIL method : (a + b) (c + d): ac + ad + bc + bd
За, b 3D 1, с %3 За, d
— За . За + За (—2) + 1 - За + 1·(-2) |
Apply minus plus rules
+(-a) = -a
3. 3aa - 3. 2a +1. 3a -1. 2
Simplify 3. 3aa – 3. 2a +1. 3a – 1. 2
3. 3aa – 3· 2a + 1. 3a – 1. 2
3. 3aa
Multiply the numbers : 3. 3 = 9 =
= 9aa
Apply exponent rule : a. a° abtc
aa = a1+1
= 9al+1
Add the numbers : 1+1 = 2
9a2
3. 2a = 6a
1. 3a = 3a
1. 2 = 2
= 9a - 6a + 3a - 2
= - 3a - 2) (3a + 4)
Expand (9a² – 3a – 2) (3a +4)
(За? — За — (3а + 4) | За - 2) (За + 4)
Distribute parentheses
= 9a? . 3a + 9a? · 4+ (-3a) · 3a
+ (-3a). 4+(-2). 3a + (-2). 4
Apply minus – plus rules
+(-a) : -a
= 9. 3a?a +9. 4a? - 3. Заа- 3 . 4а
2. 3a 2. 4
+(-a) = -a
=
2. 3a - 2.4
Simplify 9 3a?a + 9. 4a?
3. 4a - 2. 3a – 2. 4
3. 3aa
9. 3a²a + 9. 4a2 - 3. 3aa - 3. 4a - 2.
За 2. 4
9. 3a?a
Multiply the numbers : 9- 3 = 27
= = 27a-a
Apply exponent rule : a. a = abte
a?a = a2+1
27a2+1
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