(3a^2+2b^2)^2 + (3a^2-2b)^2
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Answer:
We have,
( 3a^2+2b^2)^2+(3a^2+2b^2)
so,
= 2(a^2 +b^2)
= 2(3a^2^2+2b^2^2)
= 2(9a^4+4b^4)
= 18a^4+7b^4.
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