Question

3a ² - 62-c2 + 2ab-2bct 2ca. please solve this factorisation ​

Answer 1

Answer:

ok

Step-by-step explanation:

sorry i don't know ans

Answer 2

Answer:

Given, 3a2 – b2 – c2 + 2ab – 2bc + 2ca

⇒ 4a2 – a2 – b2 – c2 + 2ab – 2bc + 2ca

⇒ (2a)2 – (a2 + b2 + c2 – 2ab + 2bc – 2ca)

⇒ (2a)2 – (a – b – c)2

[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]

⇒ (2a – (a – b – c))(2a + a + b + c)

⇒ (a + b + c)(3a + b + c)