Question

3a + 2( a + 2 ) = 10 – ( 2a – 5 )
find value of a ​

Answer 1

Step-by-step explanation:

Answer:

\

Given:

5

1

thshareinprofit.

.

\large\underline\mathfrak{Solution\: :}

Solution:

➞ \rm Ankit\: share\: = \dfrac{3}{3 + 2}Ankitshare=

3+2

3

● rm Ankit\: share: = dfrac{3}{5}Ankitshare=

5

3

➞ \rm Basant\: share\: =\dfrac{2}{3 + 2}Basantshare=

3+2

2

● \rm Basant\: share\: = \dfrac{2}{5}Basantshare=

5

2

thshareinprofit.

➠ \dfrac{2}{5} \times \dfrac{1}{5}

5

2

×

5

1

● \dfrac{2}{25}

25

2

\large\underline\mathfrak{Govind\: gets\: from\: Basant\: :}

GovindgetsfromBasant:

➠ \dfrac{3}{5} \times \dfrac{1}{5}

5

3

×

5

1

● \dfrac{3}{25}

25

3

➪ \large\underline\mathfrak{In\: case\: of\: Ankit\: :}

IncaseofAnkit:

➭ \rm New\: share\: of\: Ankit\: : \dfrac{3}{5} - \dfrac{2}{25}NewshareofAnkit:

5

3

−

25

2

● \rm New\: share\: of\: Ankit\: : \dfrac{15 - 2}{25}NewshareofAnkit:

25

15−2

● \rm New\: share\: of\: Ankit\: : \dfrac{13}{25}NewshareofAnkit:

25

13

➪\large\underline\mathfrak{In\: case\: of\: Basant\: :}

IncaseofBasant:

➭ \rm New\: share\: of\: Basant\: : \dfrac{2}{5} - \dfrac{3}{25}NewshareofBasant:

5

2

−

25

3

● \rm New\: share\: of\: Basant\: : \dfrac{10 - 3}{25}NewshareofBasant:

25

10−3

● \rm New\: share\: of\: Basant\: : \dfrac{7}{25}NewshareofBasant:

25

7

➪\large\underline\mathfrak{In\: case\: of\: Govind\: :}

IncaseofGovind:

➭ \rm New\: share\: of\: Govind\: : \dfrac{5}{25}NewshareofGovind:

25

5

\large\underbrace{\color{purple}\bf\: New\: Ratio\:}

NewRatio

➞ \rm New\: Ratio\: = \dfrac {13}{25} : \dfrac{7}{25} : \dfrac{5}{25}NewRatio=

25

13

:

25

7

:

25

5

➞ \rm New\: Ratio\: = 13 : 7 : 5NewRatio=13:7:5

\begin{lgathered}\therefore\: \rm The\: new\: profit\: and\: loss\: sharing\: ratio\: of\: the\: partners\: 13 : 7 : 5.\\\end{lgathered}

∴Thenewprofitandlosssharingratioofthepartners13:7:5.