Question

3a-2a-ab(a-b+ab)+3ab+b-a

Answer 1

Answer:

3a-2a-a^2b+ab^2-a^2b^2+3ab+b-a

=3a-3a-a^2b+ab^2-a^2b^2+3ab+b

=a^2b+ab^2-a^2b^2+3ab+b.....Ans

Answer 2

$3a-2a-ab(a-b+ab)+3ab+b-a$$=-a^2b+ab^2-a^2b^2+3ab+b$

Step-by-step explanation:

We have,

$3a-2a-ab(a-b+ab)+3ab+b-a$

To evaluate $3a-2a-ab(a-b+ab)+3ab+b-a=?$

∴ $3a-2a-ab(a-b+ab)+3ab+b-a$

$=3a-2a-a^2b+ab^2-(ab)^2+3ab+b-a$

$=3a-2a-a^2b+ab^2-a^2b^2+3ab+b-a$

$=3a-a-2a-a^2b+ab^2-a^2b^2+3ab+b$

$=3a-3a-a^2b+ab^2-a^2b^2+3ab+b$

$=-a^2b+ab^2-a^2b^2+3ab+b$

Hence, $3a-2a-ab(a-b+ab)+3ab+b-a$$=-a^2b+ab^2-a^2b^2+3ab+b$