Math, asked by NikhilMadkar, 1 day ago

3a-2b=-10;2a+3b=2 in substitution methods ​

Answers

Answered by RohitVaishnavv
1

Answer:

The Correct Answer is a = -2 and b = 2

Step-by-step explanation:

First Equation: 3a - 2b = -10

Second Equation: 2a + 3b = 2

Now solving the first equation,

3a = -10 + 2b

a = (-10 + 2b) / 3 ---- (iii)

Now we have the value of 'a' in terms of 'b'

Therefore substituting in second equation,

2( (-10 + 2b) / 3) + 3b = 2

(-20 + 4b)/3 + 3b = 2

[(-20 + 4b) + 9b]/3 = 2

-20 + 4b + 9b = 6

-20 + 13b = 6

13b = 26

b = 2

Now putting value of 'b' in equation (iii)

a = (-10 + 2(2))/3

a = (-10 + 4)/3

a = -6/3

a = -2

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