3a-2b=-10;2a+3b=2 in substitution methods
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Answer:
The Correct Answer is a = -2 and b = 2
Step-by-step explanation:
First Equation: 3a - 2b = -10
Second Equation: 2a + 3b = 2
Now solving the first equation,
3a = -10 + 2b
a = (-10 + 2b) / 3 ---- (iii)
Now we have the value of 'a' in terms of 'b'
Therefore substituting in second equation,
2( (-10 + 2b) / 3) + 3b = 2
(-20 + 4b)/3 + 3b = 2
[(-20 + 4b) + 9b]/3 = 2
-20 + 4b + 9b = 6
-20 + 13b = 6
13b = 26
b = 2
Now putting value of 'b' in equation (iii)
a = (-10 + 2(2))/3
a = (-10 + 4)/3
a = -6/3
a = -2
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