Question

3a-2b=-10;2a+3b=2.Solve by Elimination method​

Answer 1

Answer:

a=(-2), b=2

Step-by-step explanation:

3a-2b=(-10)--eq1

2a+3b=2--eq2

Multiply eq1 by 2 and eq2 by 3

(3a-2b=(-10))×2

=6a-4b=(-20)--eq3

(2a+3b=2)×3

=6a+9b=6--eq4

Add eq3 and eq4, we get

(-13b)=(-26)

13b=26

b=26/13

b=2

Substitute b=2 in eq2

2a+3b=2

2a+3(2)=2

2a+6=2

2a=2-6

2a=(-4)

a=(-4)/2

a=(-2)

Answer 2

Answer:

Step-by-step explanation:

3a - 2b = -10

-2a + 3b = 2

     5b = 8