3a + 2b = 12 2a +3b = 13 simultaneous equation
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3a+2b=12................ (1)
2a+3b=13...................(2)
6a+4b =24....................(3)
6a+4b=26............. (4)
subtraction 4-3
6a+4b-6a-4b=26-24
0=2
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.multiply eq1 by 2 and eq2 by 3
6a+4b=24,6a+ 9b=39
6a+4b=24
6a+9b=39
-. -. -
-5b =63
b=-63/5
put the value of b in eq1
3a+2b=12
3a+2×63/5=12
3a+126/5=12
3a+126=12×5
3a+126=60
3a=60-126
3a=-66
a=-66/3
a=-22
so a=-22. ; b=-63/5
HOPE IT WILL MAKE SENSE AND HELP YOU
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