Question

(-3a+2b)² expand using suitable identity
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Answer 1

(-3a+2b)² expand using suitable identity

3a-2b)³=(3a)³-(2b)³-3(3a)(2b)[(3a)-(2b)]
(3a-2b)³=27a³-8b³-18ab(3a-2b)
(3a-2b)³=27a³-8b³-54a²b+36ab²(ANSWER)
Since (a-b)³=a³+b³-3ab(a-b)

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Answer 2

Answer:

(3a-2b)³=(3a)³-(2b)³-3(3a)(2b)[(3a)-(2b)]

(3a-2b)³=27a³-8b³-18ab(3a-2b)

(3a-2b)³=27a³-8b³-54a²b+36ab²(ANSWER)

Since (a-b)³=a³+b³-3ab(a-b)