3A ⇌ 2B + 3C
at starting 3 mole A are taken, if degree of dissociation is x , find total no. of mole at equilibrium..
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Answer:
(a-aα)/2
Explanation:
Given that
A3(g) ⇌ 3A(g)
initially
a 0
At equilibrium
a−x 3x (x=aα).
a−aα 3aα
Total number of moles at equilibrium
=a−aα+3aα=a(1+2α).
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