Math, asked by vithikamishra3, 2 days ago

3a-2b-ab-(a-b+ab)+3ab+b-a ​

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Answered by dayanidhisharma19
2

Answer:

a(1+b)

Step-by-step explanation:

According to the BODMAS rule we simplify the following:

3a-2b-ab-(a-b+ab)+3ab+b-a ​\\= 3a-2b-ab-a +b-ab+3ab+b-a ​\\= a(3-1-1) + b(-2+1+1) + ab(-1-1+3)\\= a(1) + b(0) +ab(1)\\= a + 0 + ab\\= a + ab\\= a(1+b)

Answered by krishpmlak
0

Answer:

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