Question

3a+2b+c=0,then value of 27acube+8bcube+ccube=?​

Answer 1

Step-by-step explanation:

Given, 3a + 2b = 5c ...............1

take cube on both side, we get

(3a + 2b)3 = (5c)3

=> (3a)3 + (2b)3 + 3 * 3a * 2b * (3a + 2b) = 125c3

=> 27a3 + 8b3 + 3 * 3a *2b * 5c = 125c3 {from equation 1}

=> 27a3 + 8b3 + 90abc = 125c3

Given, abc = 0

=> 27a3 + 8b3 + 90 * 0 = 125c3

=> 27a3 + 8b3 + 0 = 125c3

=> 27a3 + 8b3 = 125c3

=> 27a3 + 8b3 - 125c3 = 0

So, the value of 27a3 + 8b3 - 125c3 is 0