Question

3a-2b+c=0 then value of 9a²-4b²+c²+6ac id ​

Answer 1

Step-by-step explanation:

3a-2b+c=0

(3a-2b+c)^2=(0)^2{Do squaring in both sides}

(3a)^2+(-2b)^2+(c)^2+2×3a×(-2b)+2×(-2b)×c+2×c×3a=0

9a^2-4b^2+c^2-12ab-4bc+6ac=0

9a^2-4b^2+c^2+6ac=0+12ab+4bc=12ab+4bc

Answer 2

Answer:

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