3a(2b+c)-4(a+b)c-4a(a+b+c)-2b(a+b-c)
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6ab+3ac-4a-4b-4a2-4ab-4ac-2ab-2b2+2bc=ac-4a-4b-4a2-2b2+2bc
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Answer:
4ab-5ac-6bc-4a^2+2b^2
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