Question

(3a+2b)+(p+4q)+(x+2y)[tex]x^{2}

Answer 1

Given:

Given expression is, $(3a+2b)+(p+4q)+(x+2y)x^{2}$.

To find:

We need to simplify the given expression.

Solution:

To simplify any type of expression, we need to remove complex terms, brackets etc.

Consider the given expression,

$\Rightarrow (3a+2b)+(p+4q)+(x+2y)x^{2}$

Multiplying the last two terms, we get

$\Rightarrow (3a+2b)+(p+4q)+x^3+2yx^{2}$

Removing extra brackets, we get

$\Rightarrow 3a+2b+p+4q+x^3+2yx^{2}$

Rearranging the terms, we get

$\Rightarrow x^3+2x^{2}y+3a+2b+p+4q$

The above expression cannot be simplified further because there are no complex terms in the above expression. So, it is the final answer.

Therefore, the value of given expression after simplifying it, is equal to

$x^3+2x^{2}y+3a+2b+p+4q$.