Question

(3a+4) (2a-3) + (5a-4) (a+2)

Answer 1

Answer:

$\red { (3a+4) (2a-3) + (5a-4) (a+2)}$

$\green {=11a^{2}+5a-20}$

Step-by-step explanation:

(3a+4)(2a-3)+(5a-4)(a+2)

= 3a(2a-3)+4(2a-3)+5a(a+2)-4(a+2)

= 6a²-9a+8a-12+5a²+10a-4a-8

= 6a²+5a²-9a+8a+10a-4a-12-8

= 11a²+(-9+8+10-4)a-20

= 11a² + 5a - 20

Therefore.,

$\red { (3a+4) (2a-3) + (5a-4) (a+2)}$

$\green {=11a^{2}+5a-20}$

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