Question

(3a+4b)=18. ab=4 find value of (9a^2+16b^2)

Answer 1

Answer:

228

Step-by-step explanation:

here is you answer for the question

Answer 2

Answer:

Here,

→ 3a + 4b = 18

Square on both sides :

→ ( 3a + 4b )² = 18²

Using ( a + b )² = a² + b² + 2ab

→ ( 3a )² + ( 4b )² + 2( 3a * 4b ) = 324

→ 9a² + 16b² + 2( 12 ab ) = 324

Given ab = 4

→ 9a² + 16b² + 2( 12 * 4 ) = 324

→ 9a² + 16b² + 2( 48 ) = 324

→ 9a² + 16b² + 96 = 324

→ 9a² + 16b² = 324 - 96

→ 9a² + 16b² = 228

Hence the required sum is 228