Question

(3a-4b+2c)² solve this please​

Answer 1

(a+b+c)²= a²+b²+c²+2ab+2bc+2ca

{3a+(-4b)+2c}²= (3a)²+(-4b)²+(2c)²+{2×3a×(-4b)}+{2×(-4b)×2c}+{2×2c×3a}

=>9a²+16b²+4c²+(-24ab)+(-16bc)+12ac

=>9a²+16b²+4c²-24ab-16bc+12ac

Hope it helps you !!!!

Answer 2

$<marquee>✌9a²+16b²+4c²-24ab-16bc+12ac✌</marquee>$

(a+b+c)²=a²+b²+c²+2ab+2bc+2ac

Therefore,

(3a-4b+2c)²=(3a)²+(-4b)²+(2c)²+2(3a)(-4b)+2(-4b)(2c)+2(2c)(3a)(3a)=9a²+16b²+4c²-24ab-16bc+12ac.