(3a + 4b)^3 plz solve it with identity
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hi...
id== a^3 + b^3 + 3a^2b + 3ab^2
== 3a^3+4b^3+(3×3a^2×4b)+(3×3a×4b^2)
==27a^3+64^3+ 108ab+144ab
is ur answer......
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