Question

3a-4b=4
2a+3b=14
Solve by SUBSTITUTION METHOD.
STEP BY STEP

Answer 1

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Answer 2

The correct answer is a = 4 and b = 2.

Given: The equations = 3a-4b=4 and 2a+3b=14.

To Find: The value of a and b.

Solution:

The equations = 3a-4b=4 and 2a+3b=14.

Taking 3a-4b = 4.

3a = 4+4b

a = $\frac{4+4b}{3}$

Now put the value of a in 2a+3b=14.

$2(\frac{4+4b}{3})+3b=14$

$(\frac{8+8b+9b}{3})=14$

$(\frac{8+17b}{3})=14$

8 + 17b = 42

17b = 34

b = 2

Put the value of b in a = $\frac{4+4b}{3}$.

$a=\frac{4+4b}{3}=\frac{4+4(2)}{3}$

a = 4

Hence, the value of a and b is 4 and 2 respectively.

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