Question

3a+4b=43 & -2a+3b=11 solve the simultaneous equation

Answer 1

Answer:

3a+4b=43......(1)

-2a+3b=11.......(2)

Multiply (1)by 2 and (2)by 3 ,we get

6a+8b=86......(3)

-6a+9b= 33.......(4)

On adding eq.(3) and (4), we get

17b= 119

b=119/17

b=7

by putting the value of b in equation (1), we get

3a+28=43

3a= 15

a=15/3=5

so a= 5 and b= 7

Step-by-step explanation:

hopefully it's helpful

Answer 2

Step-by-step explanation:

3a+4b = 43-------1

-2a+3b = 11-------2

Multiplying by 3 in equ 1 and 4 in equ 2, after subtracting we get,

9a+12b-8a-12b=129-144

Here 12b is cut from - 12b (don't mention it)

17a = 85

a = 5

Putting the value of a in equ 1 we get,

3*5+4b=43

15+4b=43

4b=43-15

4b=28

b=7

Here a=5,and b= 7

Hopes it will be helpful for you