Question

3a_4b+4c,2a+3b_8c,a_6b+c​

Answer 1

3a−4b+4c)+(2a+3b−8c)+(a−6b+c)

=3a+2a+a−4b+3b−6b+4c−8c+c

=6a−7b−3c

Answer 2

Answer:

(3a−4b+4c)+(2a+3b−8c)+(a−6b+c)

=3a+2a+a−4b+3b−6b+4c−8c+c

=6a−7b−3c