Question

(3a+4b+5c)
$(3a + 4b + 5c) {}^{2}$



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Answer 1

$\fcolorbox{red}{cyan}{9a²+16b²+25c²+24ab+30bc+30ac}$

Step-by-step explanation:

$(3a+4b+5c)² \\ =>\bf\color{purple}{(x+y+z)²=x²+y²+z²+2xy+2yz+2xz} \\ =>\bf{Lets\:Put\:The\:Values} \\ =>[(3a)²+(4b)²+(5c)²=(2\times 3a \times 4b) + (2 \times 4b \times 5c) + (2 \times 5c \times 3a) \\ => 9a²+16b²+25c²+24ab+30bc+30ac$

Hope it helped

Answer 2

Answer:

Step-by-step explanation: