Question

3a + 4b +5c; when a- 1, b=0 and c-1​

Answer 1

Answer:

8

Step-by-step explanation:

substitute a= 1 b=0 c=1 in 3a+4b+5c

3×1+4×0+5×1

3+0+5

8

Answer 2

Answer:

a=-1,

b=0

c=-1

3a+4b+5c

=3×(-1)+4×0+5×(-1)

=-3+0-5

=-8