Question

3a+4c-9c .(a=-5,b=-2,c=-6)​

Answer 1

Answer:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴  Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Answer:

hey friend your answer is

Step-by-step explanation:

3a+4c-9c

= 3(-5)+ 4(-2) - 9(-6)

= -15+(-8)-(-54)

= -15-8+54

= -23+54

= 31

hope it helps you