3a +5b=26; a + 5b=22 please answer my question
Answers
Answered by
1
Answer:
3a+5b=26;a+5b=22
mark both of the equation as first and second respectively
now multiply second equation by 3
we get 3a+15b=66 now solve both the equations by elimination method
3a+5b=26
3a+15b=66
-10b=-40
b=4 now put the value of b in equation first
3a+5(4)=26
3a+20=26
3a=6
a=6
thanks.......,
Answered by
1
Answer:
hence a=2,b=4
Step-by-step explanation:
3a+5b=26 ____equation 1
a+5b=22_______equation 2
- - -
_________
2a =4
__________
a=4÷2
a=2
put a=2 in equation 2
2 impulse 2+5b=22
5b=22-2
5b=20
b=20÷5
b=4
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