Question

(3a-5b)^3 expand this using suitable identity

Answer 1

Hey there!!

$\huge\sf\underline{\red{Answer:-}}$

$(3a-5b){}^{3}$

${a}^3-{b}^{3}-3{a}^{2}b+3a{b}^{2}$

a=3a. ,b=-5b

${3a}^{3}-{5 b}^{3}-3({3a}{2})(5b)+3(3a)(-{5b}^{2})$

$27a{}^{3}-125b{}{^3}-295a{}^{2}b+225ab{}^{2}$

◆◆Hope it's help uh◆◆

Answer 2

Step-by-step explanation:

Heya !!

Here's your answer

To expand

(3a - 5b - c)²

It can be expanded using algebraic identity

(a + b + c)² = a²+ b²+ c² + 2ab + 2bc + 2ac

where,

a = 3a

b = (-5b)

c = ( -c)

So,

(3a +(-5b)+(-c)² = (3a)² + (-5b)² + (-c)² + 2(3a)(-5b) + 2(-5b)(-c) + 2(3a)(-c)

= 9a² + 25b² + c² - 30ab + 10bc - 6ac

is the answer