Question

3a-5b=4 and 9a=2b+7 solve by elimination

Answer 1

Step-by-step explanation:

here

3a-5b= 4 ----(a)

Multiplying the whole equation by 3 we have

3(3a-5b=4)

= 9a-15b= 12 ----(b)

Now Subtracting b from the equation 9a= 2b+7 we have

9a= 2b+7

=> (9a-2b= 7)-( 9a-15b=12)

=> 9a-2b-9a+15b= 7-12

=> 13b =(-5)

=>b= -5/12

Now in (a)

3a-5b = 4

=> 3a-(-5/52)= 4( b = 3/13)

=> 3a= 4-5/52

=> 3a= 208-5/52

=> 3a= 203/52

=> a= 203/52*3

=>a = 203/ 156

So we have

a= 203/156

b = -5/12

hope it helps ✌

Answer 2

Answer:

Step-by-step explanation: