(3a–5b–7c)² expand it according to algebric identity
Answers
Answered by
68
(3a -5b-7c)²
here a=3a,b=-5b,c=-7c
using (a+b+c)² =a² +b²+c² +2ab+2bc+2ca
=(3a)² +(-5b)² +(-7c)² +2×3a×-5b+2×-5b×-7c+2×-7c×3a
=9a²+25b²+49c²-30ab+70bc-42ac
here a=3a,b=-5b,c=-7c
using (a+b+c)² =a² +b²+c² +2ab+2bc+2ca
=(3a)² +(-5b)² +(-7c)² +2×3a×-5b+2×-5b×-7c+2×-7c×3a
=9a²+25b²+49c²-30ab+70bc-42ac
Answered by
20
Answer:
(3a-5b-7c)²=9a²+25b²+49c²-30ab+70bc-42ca
Step-by-step explanation:
(3a-5b-7c)²
By using (a+b+c)²=a²+b²+c²+2ab+2bc+2ca
3a²+(-5b)²+(-7c)²+2*3a*(-5b)+2*(-5b)*(-7c)+2*3x*(-7c)
9a²+25b²+49c²-30ab+70bc-42ca
Hope it will help you .
Similar questions