Question

3a(a+b+c)-2b(a-b+c) from 4c(-a+b+c)

Answer 1

Answer:

$\bold{-3a^2 - 2b^2 + 4c^2 - ab + 6bc - 7ac}$

Step-by-step explanation:

$4c(-a+b+c) - [3a(a+b+c) - 2b(a-b+c)]\\\\= -4ac + 4bc + 4c^2 - (3a^2+3ab+3ac - 2ab+2b^2-2bc)\\\\= -4ac + 4bc + 4c^2 - (3a^2 + 2b^2 + ab+3ac-2bc)\\\\= -4ac + 4bc + 4c^2 - 3a^2 - 2b^2 - ab - 3ac + 2bc\\\\= \bold{-3a^2 - 2b^2 + 4c^2 - ab + 6bc - 7ac}$