Question

3a(a+b+c) _2b(a_b+c) from 4c ( _a +b+c)
please do fast as well.

Answer 1

Answer:

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3a (a + b + c) − 2b (a − b + c)

  = 3a2 +3ab + 3ac − 2ba + 2b2 − 2bc

= 3a2 + 2b2 + ab + 3ac − 2bc 4c (− a + b + c)

= − 4ac + 4bc + 4c2 Subtracting these expressions, we obtain

Therefore,

The result is −3a2 −2b2 + 4c2 − ab + 6bc − 7ac.

Answer 2

[HeY Mate]

Answer:

=> 3a (a + b + c) − 2b (a − b + c)

= 3a2 +3ab + 3ac − 2ba + 2b2 − 2bc

= 3a2 + 2b2 + ab + 3ac − 2bc 4c (− a + b + c)

= − 4ac + 4bc + 4c2

Subtracting these expressions,

Hence,

The result is −3a2 −2b2 + 4c2 − ab + 6bc − 7ac.

I Hope It Helps You✌️