Question

3a^-b+2a^-b where a=2 and b=3​

Answer 1

Answer:

$\frac{35}{1728}$

Step-by-step explanation:

$3a^{-b} +2a^{-b}$

Given that a=2 and b=3.

=$3(2)^{-3} +2(2)^{-3}$

=$6^{-3} +4^{-3}$

=$\frac{1}{6^{3} } +\frac{1}{4^{3} }$

=$\frac{1}{216} +\frac{1}{64}$

=$\frac{8+27}{1728}$

=$\frac{35}{1728}$

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