Question

(3a+b)+(3a-b). y+(x-z)​

Answer 1

Answer:

(4a−3b)3−(3a−b)3−(a−2b)3

=(4a−3b)3+(b−3a)3+(2b−a)3

Let,

x=4a−3b;y=b−3a;z=2b−a

On adding, x+y+z=0

∴x3+y3+z3=3xyz

Subtituting x, y, z values, we get

(4a−3b)3+(b−3a)3+(2b−a)3

=3(4a−3b)(b−3a)(2b−a)

Step-by-step explanation:

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