3a -b = 4 & -1 a -5b = -10
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According to given sum,
=> 3a-b =4.................. (1)
=> -a-5b=-10.............(2)
Multiply eq(2) with 3 , we get
=> -3a-15b =-30.......... (3)
Adding eq(1) & (3)
=> 3a-b-3a-15b = 4-30
=> -16b = -26
=> b = -26/-16
=> b =13/8.
substitute the value of b in eq(1).
=> 3a-13/8 = 4
=> 3a=4+13/8 => 45/8
=> a =45/(8×3)
=> a= 15/8.
:-)Hope it helps u.
=> 3a-b =4.................. (1)
=> -a-5b=-10.............(2)
Multiply eq(2) with 3 , we get
=> -3a-15b =-30.......... (3)
Adding eq(1) & (3)
=> 3a-b-3a-15b = 4-30
=> -16b = -26
=> b = -26/-16
=> b =13/8.
substitute the value of b in eq(1).
=> 3a-13/8 = 4
=> 3a=4+13/8 => 45/8
=> a =45/(8×3)
=> a= 15/8.
:-)Hope it helps u.
suyogbansode:
wrong answer
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