Question

3a-b and 6b-a are the adjacent sides of a rectangle then it's perimeter is??

Answer 1

perimeter =2 (l+b)
so perimeter = 2 (3a-b + 6b-a)
=2×(2a+5b)
=4a+10b
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Answer 2

Heya !!

Here is ur answer

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Given :-

Adjacent sides of rectangle :-

➡ 3a -b

➡ 6b -a

Question :- perimeter ??

________

Perimeter of rectangle = 2( l+B)

________

Here l = 3a-b ; b = 6b -a

Perimeter = 2[ ( 3a-b + 6b -a ) ]

➡ 2 ( 2a +5b )

➡ 4a + 10b

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Hence the perimeter of given rectangle is 4a +10b

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Hope it helps u..!!