Physics, asked by bahzadafroz, 1 month ago

3A lamp consumes 1200j energy in 12 s. what is its power

Answers

Answered by anushakm322

0

Answer:

answer is P=100J/s

Explanation:

given

energy E= 1200J

time ∆t=12s

formula for power is P=E/∆t

P=1200/12

P=100J/s

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