Question

3a2 + 12a + 12
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Answer 1

Answer:

3 ( a + 2 )²

Step-by-step explanation:

3a² + 12a + 12

By Middle Term Factorization

= 3a² + 6a + 6a + 12

= 3a ( a + 2 ) + 6 ( a + 2 )

= ( a + 2 ) ( 3a + 6 )

= ( a + 2 ) 3 ( a + 2 )

= 3 ( a + 2 )²

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Answer 2

Answer:

$p(a) = 3a ^{2} + 12a + 12 \\ let \: p(a) = 0 \\3a ^{2} + 12a + 12 = 0 \\ 3a^{2} + 6a + 6a + 12 = 0 \\ 3a(a + 2) + 6(a + 2) = 0 \\(a + 2)(3a + 6) = 0 \\ a + 2 = 0 \: \: and \: \: 3a + 6 = 0 \\ a = - 2 \: \: and \: a = - 6 \div 3 \: \: \: \: a = - 2 \\ verification \\ p( - 2) = 3( - 2) ^{2} + 12( - 2) + 12 = 0 \\ 3(4) - 24 + 12 = 0 \\ 12 - 24 + 12 = 0 \\ 24 - 24 = 0$

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