3a²+36a+121 =?
Please answer?
Answers
Answer:
Final result :
3a2 + 36a + 121
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(3a2 + 36a) + 121
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 3a2+36a+121
The first term is, 3a2 its coefficient is 3 .
The middle term is, +36a its coefficient is 36 .
The last term, "the constant", is +121
Step-1 : Multiply the coefficient of the first term by the constant 3 • 121 = 363
Step-2 : Find two factors of 363 whose sum equals the coefficient of the middle term, which is 36 .
-363 + -1 = -364 -121 + -3 = -124 -33 + -11 = -44 -11 + -33 = -44 -3 + -121 = -124 -1 + -363 = -364 1 + 363 = 364 3 + 121 = 124 11 + 33 = 44 33 + 11 = 44 121 + 3 = 124 363 + 1 = 364
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
3a2 + 36a + 121