Question

3a2-4b2+6a2-4b+7b2-(5a-3b+6a2)​

Answer 1

Algebraic operations

Given: three expressions 3a² - 4b², 6a² - 4b + 7b² and 5a - 3b + 6a²

To find: (3a² - 4b²) + (6a² - 4b + 7b²) - (5a - 3b + 6a²)

Solution:

• Now, (3a² - 4b²) + (6a² - 4b + 7b²) - (5a - 3b + 6a²)
• = 3a² - 4b² + 6a² - 4b + 7b² - 5a + 3b - 6a²
• = 3a² + 6a² - 6a² - 4b² + 7b² - 5a - 4b + 3b
• = (3 + 6 - 6) a² + (- 4 + 7) b² - 5a - (4 - 3) b
• = 3a² + 3b² - 5a - b
• This is the required value.

Answer: (3a² - 4b²) + (6a² - 4b + 7b²) - (5a - 3b + 6a²) = 3a² + 3b² - 5a - b

Remember:

• Rearrange the like terms
• Group them
• Perform additions & subtractions
• Write the answer