Question

3a2-6ab-362-1 to get 4a2-7ab-4b2+1? A) -a?+ab+b2-2 B) a2 + ab +62+2 C) al-ab-b2+2 D) a2-ab-4b2-2​

Answer 1

Answer:

$tanA=2−1</p><p></p><p></p><p>tanA=ABBC=12−1</p><p></p><p></p><p> AC2=BA2+BC2=12+(2−1)2=1+2−22+1</p><p></p><p></p><p> AC=4−22</p><p></p><p></p><p> sinA=ACBC=4−222−1cosA=ACAB=4−221</p><p></p><p></p><p> sinA×cosA=4−222−1×4−221=4−222−1</p><p></p><p></p><p> =22(2−1)2−1=221×22=42</p><p></p><p></p><p> cosA×cosAsinA×cosA=42</p><p></p><p></p><p>Multiply numerator & denominator by cosA</p><p></p><p> </p><p></p><p> sec2AtanA=42⇒1+tan2AtanA=42</p><p></p><p></p><p>$

hope it will help u