Math, asked by Manish12345677, 7 months ago

3a2-7b2-7c2-2ab+19bc-2ac

Answers

Answered by shashankpaib
1

Step-by-step explanation:

3a2-b2-c2+2ab-2bc+2ca

3a²−b²−c²+2ab−2bc+2ac  

=4a²−a²−b²−c²+2ab−2bc+2ac  

=4a²−(a²+b²+c²−2ab+2bc−2ac)  

=(2a)²−(a−b−c)²  

=(2a+a−b−c)(2a−a+b+c)  

=(3a−b−c)(a+b+c)

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