Math, asked by StarTbia, 1 year ago

3a²–8ab–2b² , 3a²–4ab+6b²,Subtract the second expression from the first expression.

Answers

Answered by TheUrvashi
34
Heyaa!!

Solution:-

3a²- 8ab - 2b²- (3a²- 4ab + 6b²)

=3a²- 8ab - 2b²- 3a² + 4ab - 6b²

= - 4ab - 8b².

Thanks

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Answered by abhi569
30
From the given equations : —
3a² - 8ab - 2b² , 3a² - 4ab + 6b²



First Equation : 3a² - 8ab - 2b²

Second Equation : 3a² - 4ab + 6b²



Subtracting second expression from first expression : —


→ 3a² - 8ab - 2b² - ( 3a² - 4ab + 6b² )

→ 3a² - 8ab - 2b² - 3a² + 4ab - 6b²

→ 3a² - 3a² - 8ab + 4ab - 2b² - 6b²

→ - 4ab - 8b²



Therefore, on subtracting the second expression from the second expression we get - 4ab - 8b².
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