Question

(3a2-a+3)+(4a2-5)
find each sum or difference. answers must in standard form

Answer 1

Answer:

$(3 {a}^{2} - a + 3) + (4 {a}^{2} - 5) \\ 7 {a}^{2} - a - 2$

This will help you

Answer 2

12a - 2 = 0

12a - 2 = 0a = 6

• ( 3a2 - a + 3 ) ( 4a2 - 5)

• = ( 6a - a + 3 ) ( 8a - 5 )

• = ( 5a + 3 ) ( 8a - 5 )

• = 5a + 3 + 8a - 5

• = 12a - 2

Standard form ,

• 12a - 2 + 0 = 0

• 12a = 2

• a = 12 / 2

• a = 6