3a² bc, - 3abc², 3a²bc and 2abc²
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Answer:
parth verma
Step-by-step explanation:
Given terms are 7a
2
bc , −3abc
2
, 3a
2
bc , 2abc
2
Required sum =7a
2
bc+(−3abc
2
)+(3a
2
bc)+(2abc
2
)
Rearranging and collecting like terms,
=7a
2
bc+3a
2
bc−3abc
2
+2abc
2
=(7+3)a
2
bc+(−3+2)abc
2
=10a
2
bc−abc
2
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