Math, asked by suyashtiwari606, 3 months ago

3a²b+12 a2 +9b +36 factorise

Answers

Answered by s13397adisha2258

8

Answer:

3a2b - 12a2 - 9b + 36 = 3a2(b - 4) - 9(b - 4) = (b - 4) (3a2 - 9) = (b - 4) 3(a2 - 3) = 3(b - 4) (a2 - 3)-3a-2b-12a-2-9b-36

Answered by bianca3672

2

Answer:

3a2b-12a2-9b+36

=3a2(b-4)-9(b-4) by grouping

(b-4) (3a2-9)=(b-4)(a2-3)

=3(b-4)(a2-3)

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