3a²b+12 a2 +9b +36 factorise
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Answered by
8
Answer:
3a2b - 12a2 - 9b + 36 = 3a2(b - 4) - 9(b - 4) = (b - 4) (3a2 - 9) = (b - 4) 3(a2 - 3) = 3(b - 4) (a2 - 3)-3a-2b-12a-2-9b-36
Answered by
2
Answer:
3a2b-12a2-9b+36
=3a2(b-4)-9(b-4) by grouping
(b-4) (3a2-9)=(b-4)(a2-3)
=3(b-4)(a2-3)
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