Question

3a²b+ 4ab²-a²b-3ab²+a²b²

Answer 1

$Given \: 3a^{2}b+4ab^{2}-a^{2}b-3ab^{2}+a^{2}b^{2}$

/* Rearranging the terms,we get */

$= 3a^{2}b-a^{2}b+4ab^{2}-3ab^{2}+a^{2}b^{2}$

$= (3-1)a^{2}b+(4-3)ab^{2}+a^{2}b^{2}$

$= 2a^{2}b+ab^{2}+a^{2}b^{2}$

$= ab( 2a+b+ab)$

Therefore.,

$\red{3a^{2}b+4ab^{2}-a^{2}b-3ab^{2}+a^{2}b^{2} }$

$\green {= ab( 2a+b+ab) }$

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