Math, asked by parmilakumari9810, 9 months ago

-3a²b²+(-5/2)a²b²+4a²b²+(2/3)a²b²

Answers

Answered by satyasreevanka
5

Lets take a²b² common

  • a²b²( -3+(-5/2)+4+(2/3))
  • a²b²( 1+(2/3)-(5/2))
  • a²b²(-5/6)
  • -(5/6) a²b²

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Answered by Anonymous
7

\large\underline\mathrm\red{Answer \: :}

= -3a²b²+\frac {-5}{2} a²b²+4a²b²+ \frac {2}{3} a²b²

= -3a²b²- \frac {5}{2} a²b²+4a²b²+ \frac {2}{3} a²b²

=  \frac {-5}{6} a²b²

\boxed {\frac {-5}{6}a²b² }

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